2z(3z+,05)=6z^2-6,5

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Solution for 2z(3z+,05)=6z^2-6,5 equation: 



2z(3z+.05)=6z^2-6.5

We move all terms to the left:

2z(3z+.05)-(6z^2-6.5)=0

We add all the numbers together, and all the variables

2z(3z+0.05)-(6z^2-6.5)=0

We multiply parentheses

6z^2+0.1z-(6z^2-6.5)=0

We get rid of parentheses

6z^2-6z^2+0.1z+6.5=0

We add all the numbers together, and all the variables

0.1z+6.5=0

We move all terms containing z to the left, all other terms to the right

0.1z=-6.5

z=-6.5/0.1

z=-65

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